Electrolytic cell half reaction equations?

In summary, when choosing the species for the anode and cathode in an electrolytic cell, it is important to consider the Standard Reduction Potential and the activity of the electrolyte. In the case of aqueous aluminum chloride, H2O is chosen as the anode due to its lower SRP compared to Al. For the cathode, H2O is chosen over Cl2 due to factors such as the activity of the electrolyte and the hydrophobicity of chloride ion. However, Cl2 may still be liberated at the cathode along with oxygen due to the competition between chlorine and oxygen at the anode.
  • #1
Jack Litmus
1
0
Hi everyone, I was just wondering how I would choose which species in an electrolytic cell to use as the cathode and which to use as the anode.

For example, for aqueous aluminum chloride (inert electrodes), H2O (-0.83V) and H2O (+1.23V) will be used as the anode and cathode for the half reactions, but while I think I understand why H2O (-0.83V) is chosen has the anode over Al (everything @ Al and below will not be deposited or something if water is present), I don't understand why H2O(+1.23V) is chosen over Cl2 (+1.36) as the cathode.

Would someone please explain how to pick the anode and cathode species? Thank you!
 
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  • #2
Electrolytic cells prefer species at anode with high Standard Reduction Potential at Anode and low SRP at Cathode. But nonetheless, Cl2 will be liberated at the cathode along side Oxygen.
 
  • #3
AGNuke said:
Electrolytic cells prefer species at anode with high Standard Reduction Potential at Anode and low SRP at Cathode. But nonetheless, Cl2 will be liberated at the cathode along side Oxygen.

There are a lot of complicated issues in the chlorine/oxygen competition at an anode. Two of the main considerations are
(1) that an electrolyte is not always at 1 M activity (standard state), and any departure from this affects the potential value (Nernst equation)
(2) that chloride ion is much more hydrophobic than hydroxyl, and will tend to adsorb at the surface of any physical electrode, and therefore have a greater availability to the electrode for electron removal. Or another way of looking at it, a much greater local concentration in the immediate region of the anode surface than in the bulk electrolyte.
 

1. What is an electrolytic cell half reaction equation?

An electrolytic cell half reaction equation is a chemical equation that represents the oxidation or reduction half of a redox reaction that occurs in an electrolytic cell. It shows the transfer of electrons and the formation of products from reactants.

2. How are electrolytic cell half reaction equations balanced?

Electrolytic cell half reaction equations are balanced by making sure that the number of atoms of each element is the same on both sides of the equation. This is done by adding coefficients to the reactants and products as needed.

3. What is the purpose of balancing electrolytic cell half reaction equations?

The purpose of balancing electrolytic cell half reaction equations is to ensure that the law of conservation of mass is obeyed. This means that the number of atoms of each element must be the same on both sides of the equation.

4. How do you determine the oxidation state of an element in an electrolytic cell half reaction equation?

The oxidation state of an element in an electrolytic cell half reaction equation can be determined by using a set of rules, such as the rule that the oxidation state of a free element is always 0, and the sum of the oxidation states of all elements in a compound must equal the overall charge of the compound.

5. What factors can affect the rate of a reaction in an electrolytic cell?

The rate of a reaction in an electrolytic cell can be affected by several factors, such as the concentration of reactants, the temperature, the surface area of the electrodes, and the presence of a catalyst. These factors can increase or decrease the rate of the reaction by affecting the number of collisions between particles and the energy of those collisions.

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