The 1/2 equivalent point in a titration curve

  • #1
Saba
7
2
TL;DR Summary
It is pretty challenging for me to understand how the 1/2 equivalent point in a titration curve (when either acid or base is weak) the pH = pKa.
I researched about the formula that is used to get this, but I couldn't quite understand that.
1700561157760.png
 
Chemistry news on Phys.org
  • #2
What are expected concentrations of the remaining, non-neutralized titrated acid and its conjugate base at half point?

What is ratio of these concentrations equal to?

What is log of that?
 
  • #3
From the equation above (the Henderson-Hasselbach equation if I remember correctly), the half equivalent point is when the concentrations of the acid and its conjugate base are equal. Any number divided by itself is 1 (one). The log of 1 is 0 (zero), so therefore pH = pKa
 

What is the 1/2 equivalent point in a titration curve?

The 1/2 equivalent point in a titration curve is a stage during a titration where half of the analyte has reacted with the titrant. It is particularly significant in acid-base titrations involving weak acids or bases, as it corresponds to the point where the concentration of the weak acid equals the concentration of its conjugate base, or vice versa. This point is used to determine the pKa of the weak acid or base being titrated, as the pH at this point gives a direct reading of the pKa.

How is the 1/2 equivalent point related to the buffer capacity?

The 1/2 equivalent point in a titration curve is closely related to the maximum buffer capacity. At this point, the solution can effectively resist changes in pH upon the addition of small amounts of acid or base. This is because the concentrations of the weak acid and its conjugate base are equal, providing the optimal condition for a buffer system according to the Henderson-Hasselbalch equation.

Can the 1/2 equivalent point be determined in all types of titrations?

The 1/2 equivalent point is most commonly determined in acid-base titrations, particularly those involving a weak acid or a weak base. In titrations involving strong acids and strong bases, this point is not as distinct or useful because there isn't a significant buffering region. For redox or precipitation titrations, the concept of a 1/2 equivalent point does not apply in the same way as it does in acid-base titrations.

How do you calculate the pH at the 1/2 equivalent point?

The pH at the 1/2 equivalent point can be calculated using the Henderson-Hasselbalch equation. For a weak acid being titrated with a strong base, the equation is pH = pKa + log([A-]/[HA]), where [A-] is the concentration of the conjugate base and [HA] is the concentration of the weak acid. At the 1/2 equivalent point, the concentrations of [A-] and [HA] are equal, simplifying the equation to pH = pKa, since log(1) = 0.

What is the significance of the 1/2 equivalent point in practical applications?

In practical applications, the 1/2 equivalent point is crucial for the precise determination of the pKa of a weak acid or base, which is essential for understanding its acid-base behavior in various chemical and biological contexts. Additionally, understanding the buffer capacity at this point helps in the formulation of buffer solutions that are effective in maintaining pH stability in industrial, laboratory, or physiological environments.

Similar threads

Replies
4
Views
2K
Replies
3
Views
1K
Replies
5
Views
2K
  • Chemistry
Replies
8
Views
3K
Replies
4
Views
2K
Replies
7
Views
1K
Replies
3
Views
986
Replies
3
Views
590
  • Chemistry
Replies
4
Views
14K
  • Biology and Chemistry Homework Help
Replies
10
Views
2K
Back
Top