- #1
trulyfalse
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Hey PF!
Find exact solutions for the following equations over the domain 0 ≤ x <2π
2sinx = 3 + 2cscx
sin2+cos2=1
2sinx = 3 + 2cscx
2sinx = 3 +2(1/sinx)
sinx = 3/2 + 1/sinx
sinx - 1/sinx = 3/2
(1-1-cos2x)/sinx = 3/2
-cos2x/sinx = 3/2
cos2x/sinx = -3/2
I am perplexed by this question. Where do I go from here? How do I solve this equation?
Homework Statement
Find exact solutions for the following equations over the domain 0 ≤ x <2π
2sinx = 3 + 2cscx
Homework Equations
sin2+cos2=1
The Attempt at a Solution
2sinx = 3 + 2cscx
2sinx = 3 +2(1/sinx)
sinx = 3/2 + 1/sinx
sinx - 1/sinx = 3/2
(1-1-cos2x)/sinx = 3/2
-cos2x/sinx = 3/2
cos2x/sinx = -3/2
I am perplexed by this question. Where do I go from here? How do I solve this equation?