Question regarding change in internal energy

In summary, we discussed the amount of heat needed to raise the temperature of 0.0100 mol of helium at constant pressure from 27.0 to 67.0 C, and the change in internal energy for an ideal gas with monatomic helium. We found that the change in internal energy is given by \Delta U = nC_{v}\Delta T with C_{v} = \frac{3}{2}R. We also noted that this equation is valid regardless of whether the volume is kept constant or not.
  • #1
erik-the-red
89
1
A cylinder contains 0.0100 mol of helium at T = [tex]27.0 ^\circ \text{C}[/tex].

If the presure of the helium is kept constant, how much heat is needed to raise the temperature from 27.0 to 67.0 C?

If the gas is ideal, what is the change in its internal energy?

I got the answer for the first part correct.

My question involves some concepts.

It is because helium is monatomic that the [tex]C_v[/tex] in [tex]\Delta U = nC_{v}\Delta T[/tex] is [tex]\frac{3}{2}R[/tex], correct?
 
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  • #2
erik-the-red said:
A cylinder contains 0.0100 mol of helium at T = [tex]27.0 ^\circ \text{C}[/tex].
If the presure of the helium is kept constant, how much heat is needed to raise the temperature from 27.0 to 67.0 C?
If the gas is ideal, what is the change in its internal energy?
I got the answer for the first part correct.
My question involves some concepts.
It is because helium is monatomic that the [tex]C_v[/tex] in [tex]\Delta U = nC_{v}\Delta T[/tex] is [tex]\frac{3}{2}R[/tex], correct?
Correct.

AM
 
  • #3
So, if the volume was kept constant and the temperature was changed by the same interval, the change in internal energy would still be given by [tex]\Delta U = nC_{v}\Delta T[/tex] with [tex]C_{v} = \frac{3}{2}R[/tex]?
 
  • #4
erik-the-red said:
So, if the volume was kept constant and the temperature was changed by the same interval, the change in internal energy would still be given by [tex]\Delta U = nC_{v}\Delta T[/tex] with [tex]C_{v} = \frac{3}{2}R[/tex]?
The change in internal energy is always this. You don't have to keep the volume constant. It is just that if the volume is constant there is no work done and all the heat is used to increase internal energy so [tex]Q = \Delta U = nC_{v}\Delta T[/tex].

AM
 

What is internal energy?

Internal energy is the total energy contained within a system, including the kinetic energy of its particles and the potential energy due to their interactions.

How is internal energy related to temperature?

Internal energy and temperature are directly proportional to each other. As the temperature of a system increases, its internal energy also increases.

What factors can cause a change in internal energy?

There are several factors that can cause a change in internal energy, such as changes in temperature, pressure, volume, and the addition or removal of heat or work.

What is the first law of thermodynamics?

The first law of thermodynamics states that energy cannot be created or destroyed, but it can be converted from one form to another. This means that the change in internal energy of a system is equal to the heat added to the system minus the work done by the system.

How is the change in internal energy calculated?

The change in internal energy of a system can be calculated using the formula ΔU = Q - W, where ΔU is the change in internal energy, Q is the heat added to the system, and W is the work done by the system. The units for internal energy are typically joules (J) or calories (cal).

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