- #1
chrispsu
- 23
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im reviewing for my final in a few days an although this is a basic question i can't work out the correct answer for some reason. and i know i started the other thread below this one but i figured this was a different topic so the heading should be different lol
A heat transfer of 8.8 x 10^5 J is required to convert a block of ice at -13°C to water at 13°C. What was the mass of the block of ice?
Q=mc(ice)(tf-ti) + mLf + mc(water)(tf-ti)
i tried: 8.8x10^5= m(2220)(13) + m(333) + m(4190)(13)
i come out with the 10.52kg which is not correct.
can someone help pinpoint what i am doing something wrong? thanks!
Homework Statement
A heat transfer of 8.8 x 10^5 J is required to convert a block of ice at -13°C to water at 13°C. What was the mass of the block of ice?
Homework Equations
Q=mc(ice)(tf-ti) + mLf + mc(water)(tf-ti)
The Attempt at a Solution
i tried: 8.8x10^5= m(2220)(13) + m(333) + m(4190)(13)
i come out with the 10.52kg which is not correct.
can someone help pinpoint what i am doing something wrong? thanks!