- #1
wineesarne
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Consider f: S1 -> S1: (cos 2 pi x, sin 2 pi x) -> (cos 2 k pi x, sin 2 k pi x).
How to show directly from the homological definition (without using Hurewicz etc) that degree(f) = k?
How to show directly from the homological definition (without using Hurewicz etc) that degree(f) = k?