Objects Entering Black Holes: The "Spaghetti" Effect

In summary, the closer to center, the stronger the force that objects feel in a black hole. If an object's matter was accelerating at the same rate then why do people theorize that the object would have a "speghetti" effect?
  • #1
cooldude3122
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If an object is entering a black hole, it would be accelerating at a constant rate. If that object's matter was accelerating at the same rate then why do people theorize that the object would have a "speghetti" effect?
 
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  • #2
cooldude3122 said:
If an object is entering a black hole, it would be accelerating at a constant rate. If that object's matter was accelerating at the same rate then why do people theorize that the object would have a "speghetti" effect?

the closer to center, the stronger the force

that's true in ordinary Newtonian gravity as well
the acceleration falls off as the square of distance.
so as you get closer it increases-----if you get only half as far from center, then the acceleration is FOUR TIMES more
if you get only a third as far, the acceleration is NINE times stronger.

so at some point as you fall in, your feet will be experiencing much more acceleratation than your head

the only way for your feet to be falling faster than your head is if you are being stretched

===================
your problem is you were assuming that acceleration of gravity is constant. that is not true.
even on Earth it is different at the top of a mountain from what it is at sealevel
and it is even different at different latitudes-----they tell you in school it is 9.8 m per sec per sec
or 32 feet per sec per sec but that is just a handy approximation
 
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  • #3
cooldude3122 said:
If an object is entering a black hole, it would be accelerating at a constant rate.

Hang on a moment--- are you asking about our gold standard theory of gravitation, namely gtr? If not, what gravitation theory do you have in mind? If so, I think you are mixing up Newtonian and relativistic physics.

Certainly, if you are asking about an object which is falling freely into a black hole, as treated in gtr, then said object feels no force and its world line is a timelike geodesic. But by definition the acceleration (path curvature) of a geodesic vanishes (this happens in Lorentzian geometry for the same reason it happens in Riemannian geometry).

cooldude3122 said:
If that object's matter was accelerating at the same rate then why do people theorize that the object would have a "speghetti" effect?

Now I think you are asking about something yet again, tidal forces as treated in gtr. Indeed, an object near a compact body will feel tidal forces (in gtr, in Newtonian gravitation, in any decent gravitation theory), and these will scale rougly twice as fast radially as tangentially. In particular, an object falling into a black hole will experience radial tension and orthogonal comopression, and eventially will break and the bits will be drawn into a long thing shape as they fall. (Physics students should consult the disucssion in MTW.)

Don't confuse tidal forces on a small extended object, which are identified in gtr with (part of) the curvature tensor of spacetime itself, with acceleration of a pointlike object, which is identified in gtr with the path curvature of the world line of that object! The first kind of curvature is tensorial and has geometric units of inverse area (as does Gaussian curvature); the second kind of curvature is vectorial and has geometric units of inverse length (as does "path curvature" in the Frenet-Serret theory from the study of curves in a euclidean three-space).
 

1. What is the "spaghetti" effect in relation to objects entering black holes?

The "spaghetti" effect refers to the stretching and elongation of objects as they approach and enter a black hole. This is caused by the intense gravitational pull on different parts of the object, with the part closest to the black hole experiencing a much stronger pull than the part further away.

2. Can anything survive the "spaghetti" effect when entering a black hole?

No, the immense gravitational forces of a black hole are strong enough to tear apart any object, including stars and planets, as they approach and enter the event horizon. This is due to the extreme curvature of spacetime near a black hole.

3. How does the "spaghetti" effect impact time dilation near a black hole?

The "spaghetti" effect also causes time dilation, where time passes at a different rate for an observer outside the black hole compared to someone falling into it. As the falling observer experiences stronger and stronger gravitational forces, time appears to slow down for them, eventually appearing to stop completely at the event horizon.

4. Are there any exceptions to the "spaghetti" effect for objects entering black holes?

In theory, small particles such as photons may be able to enter a black hole without experiencing the "spaghetti" effect. This is because they have no mass and therefore do not experience the same gravitational pull. However, once they cross the event horizon, they cannot escape and will be pulled into the singularity at the center of the black hole.

5. How does the "spaghetti" effect impact our understanding of black holes?

The "spaghetti" effect is one of the key concepts in understanding the behavior and properties of black holes. It helps explain phenomena such as time dilation and the distortion of light near a black hole. Studying the "spaghetti" effect can also provide insights into the nature of gravity and the structure of spacetime near these extreme objects.

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