- #1
mathmadx
- 17
- 0
Dear all,
The question I've been struggling with is supposed to be solved using the way Lagrange's thm was proven( with number of cosets and stuff). However, it remains a mystery how to do it:
Let G be a finite group and H<G with |G|=m|H|. Proof that
[tex] g^{m!} \in H, \forall g \in G[/tex]
The question I've been struggling with is supposed to be solved using the way Lagrange's thm was proven( with number of cosets and stuff). However, it remains a mystery how to do it:
Let G be a finite group and H<G with |G|=m|H|. Proof that
[tex] g^{m!} \in H, \forall g \in G[/tex]