- #1
nymbler_064
- 26
- 0
I have just been trying to teach myself about the effect of activating and deactivating groups on electrophilic substitution. However, I am a bit confused as to why the amine group in procaine (anesthetic) is in the para position, when the aromatic ring is attached to a deactivating ester. What I am really trying to explain is why the molecule is more polar for having the amine group in the para position, as opposed to the ortho or meta positions.
The structure of procaine is available here:
http://upload.wikimedia.org/wikipedia/commons/thumb/4/4a/Procaine.svg/220px-Procaine.svg.png
Thankyou very much.
The structure of procaine is available here:
http://upload.wikimedia.org/wikipedia/commons/thumb/4/4a/Procaine.svg/220px-Procaine.svg.png
Thankyou very much.