- #1
Naeem
- 194
- 0
Hi,
Can anyone help me here!
dy/dx = 1/(x.sqrt(x^2-1)) , x>0 Note y = pi when x = 2
Here is what I did:
Let u = x^2 - 1
x^2 = u + 1
Substituting this in the above yields:
dy/dx = 1/x.sqrt(u)
Differentiating: u = x^2-1
du = 2x.dx
x = du/2.dx
Then,
dy/dx= 2/sqrt(u).du
I don't know if this is rite.
Plz help me!
Can anyone help me here!
dy/dx = 1/(x.sqrt(x^2-1)) , x>0 Note y = pi when x = 2
Here is what I did:
Let u = x^2 - 1
x^2 = u + 1
Substituting this in the above yields:
dy/dx = 1/x.sqrt(u)
Differentiating: u = x^2-1
du = 2x.dx
x = du/2.dx
Then,
dy/dx= 2/sqrt(u).du
I don't know if this is rite.
Plz help me!