# Causality with time invariance

by tutumar
Tags: causality, invariance, time
 P: 2 Assume u:R$\rightarrow$ C^n and define shift operator S($\tau$) with S($\tau$)u(t)=u(t-$\tau$) and truncation operator P($\tau$) with P($\tau$)u(t)=u(t) for t$\leq$$\tau$ and 0 for t>$\tau$ Then P($\tau$)S($\tau$)=S($\tau$)P(0) for every $\tau$>=0. Can someone please prove last statement..
 Math Emeritus Sci Advisor Thanks PF Gold P: 39,346 Looks like pretty direct computation. If u(t) is any such function, then what is$SD(\tau)u$? What is $P(\tau)S(\tau)u$? Then turn around and find $S(\tau)P(0)u$.
 P: 2 Yes, I tried that, and it just doesn't fit.. P($\tau$)S($\tau$)u(t)=P($\tau$)u(t-$\tau$)=u(t-$\tau$) if t-$\tau$<=$\tau$ and 0 for t-$\tau$>$\tau$ S($\tau$)P(0)u(t)=S($\tau$)u(t) for t<=0 and 0 otherwise=u(t-$\tau$) if t<=0 and 0 otherwise.. Well, something's got to be wrong here, but I can't see what..
 P: 305 Causality with time invariance I think your last equation is wrong. As, if we have: $$P(0)u(t)=u(t) \mbox{ if } t\leq 0 \mbox{ and } 0 \mbox{ otherwise }$$ than: $$S(\tau)P(0)u(t)=u(t-\tau) \mbox{ if } t-\tau\leq 0 \mbox{ and } 0 \mbox{ if } t-\tau>0$$ Still, I'm not able to prove the statement as in the first case you have $$t-\tau\leq\tau$$ and in this case there is $$t-\tau\leq 0$$. I'm sorry...