
#1
Oct413, 09:45 AM

P: 7

I have to work out which if these two betadecay processes are energetically possible, given that the betadecay energy of Li11 is Q = 20 MeV. The two processes are:
(1) 〖Li〗_11→〖Be〗_9+2n (2) 〖Li〗_11→〖He〗_3+〖He〗_8 I am supposed to use the energy conditions for betadecay equations, i.e.: Q={M(Z,A)M(Z+1,A)m_e } c^2 Q={M(Z,A)M(Z1,A)m_e } c^2 But I don’t know which one; in the first process the numbers of neutrons and protons both decrease by one – how is this possible? (In the second process, the number of neutrons decreases by one and the number of protons increases by one, so I guess that is betaminus). Basically, I don’t understand how the decay process works, and from then how to calculate Q when there are two daughter nuclei. So an explanation would be much appreciated. Thanks! 



#2
Oct413, 10:07 AM

Mentor
P: 10,864

This is energy conservation  the total available energy is given by the mass of ##{}^11Li##, and you have to check if that is sufficient to produce all daughter particles. 


Register to reply 
Related Discussions  
Kinetic energy of electron after beta decay  General Physics  10  
energy release from beta plus decay  Introductory Physics Homework  0  
Calculating energy released from beta decay  High Energy, Nuclear, Particle Physics  1  
neutrino energy from beta+ decay  High Energy, Nuclear, Particle Physics  1  
Incident Electron Energy in Beta Decay?  Advanced Physics Homework  0 