- #1
sugarntwiligh
- 24
- 0
Homework Statement
A 65 kg trampoline artist jumps vertically upward from the top of a platform with a speed of 5.0 m/s. (Ignore small changes in gravitational potential energy.)
a) How fast is he going as he lands on the trampoline, 3.0 m below?
ANS: 9.2m/s
NOTE: I understand how to get this, I just need help on part B.
(b) If the trampoline behaves like a spring with spring stiffness constant 6.2e4 N/m, how far does he depress it?
ANS:
Homework Equations
x = Fs/-k
k = 6.2e4 N/m
F = ma
m = 65 kg
a = {(v_2)^2 - (v_1)^s}/{2d}
The Attempt at a Solution
x = {((v_2)^2 - (v_1)^s)*65}/{2*d*6.2e4}
My value of d = x = the depression of the trampoline, so,
x = {((v_2)^2 - (v_1)^s)*65}/{2*(x)*6.2e4}.
v_1 = 9.2 m/s
v_2 = 0 m/s
2x = .0443
x = 0.22 , which is wrong :-(.
Last edited: