- #1
threewingedfury
- 29
- 0
Two particles are fixed to an x-y coordinate system:
particle 1 of charge -5.00 microCoulombs lies on the x-axis at x = + 6.00 cm and particle 2 of charge +5.00 microCoulombs lies on the y-axis at y = + 8.00 cm. Midway between the particles, what is their net electric field, in unit vector notation?
So I got:
1/4piEo x q/r^2 - 1/4piEo x q/r^2
(1/(4pi(8.85x10^-12)) x (-5 x 10^-6)/(.06)^2)i - (1/(4pi(8.85x10^-12)) x (5 x 10^-6)/(.08)^2)j
-1.248e7i + 7024847j
Is this anywhere near right?
particle 1 of charge -5.00 microCoulombs lies on the x-axis at x = + 6.00 cm and particle 2 of charge +5.00 microCoulombs lies on the y-axis at y = + 8.00 cm. Midway between the particles, what is their net electric field, in unit vector notation?
So I got:
1/4piEo x q/r^2 - 1/4piEo x q/r^2
(1/(4pi(8.85x10^-12)) x (-5 x 10^-6)/(.06)^2)i - (1/(4pi(8.85x10^-12)) x (5 x 10^-6)/(.08)^2)j
-1.248e7i + 7024847j
Is this anywhere near right?