- #1
kotreny
- 46
- 0
I don't know where to begin to calculate this limit, but I think I know what the answer is. Could someone please do it with straightforward methods? I suspect the answer is ln(x+1).
Also, I don't know how to write it down in proper notation, so I ask that someone do that too.
limdx-->0 SUMk=1 to x/dx[dx/(1+(k-1)dx)]
Also, I don't know how to write it down in proper notation, so I ask that someone do that too.
limdx-->0 SUMk=1 to x/dx[dx/(1+(k-1)dx)]