- #1
egrus8
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Could someone help with this problem I don't know how to set it up with the worker pushing parallel to the floor instead of the plane.
A UPS worker is loading a truck by pushing boxes weighing 120 kg up a ramp that makes an angle of 32 degrees above the floor. The coefficients of friction between a box and the ramp are 0.62 and 0.43.
What push must the worker exert parallel to the floor (not the plane) to cause the box to accelerate up the plane at an acceleration of 0.8
the formula for parallel to the plane is P=ma + mgsin(θ)+μ(mgcos(θ) for the push, the part I am having trouble with is how to get the formula for parallel to the floor instead of the plane? Any help will be truly appreciated.
A UPS worker is loading a truck by pushing boxes weighing 120 kg up a ramp that makes an angle of 32 degrees above the floor. The coefficients of friction between a box and the ramp are 0.62 and 0.43.
What push must the worker exert parallel to the floor (not the plane) to cause the box to accelerate up the plane at an acceleration of 0.8
the formula for parallel to the plane is P=ma + mgsin(θ)+μ(mgcos(θ) for the push, the part I am having trouble with is how to get the formula for parallel to the floor instead of the plane? Any help will be truly appreciated.