- #1
danyalasdf
- 6
- 0
Homework Statement
We did something very similar to this in lab
http://webenhanced.lbcc.edu/physte/phys2ate/2A LAB HANDOUTS/Moment of Inertia.pdf
Use Newton's Second to derive the expression for the experimentally determined moment of inertia
Homework Equations
Newton's Second Law is F=m*a
s=(1/2)*a*t^2
Experimentally Moment of Inertia
I=r^2(m((gt^2/2s)-t) - mf)
Trying to get to this ^
mf= mass effective not much meaning just mass in kg
If it confusing the gt^2 is divided by 2s then it is subtracted by t and multiplied by r^2 and then minus mf
Torque= F*r= m*r*a
T= (mf + m)(g - a) = tension
The Attempt at a Solution
T= (mf + m)(g - (2*s/t^2))
T= (mf + m)((1/2)(a*t^2) - a)
T= (mf + m)(a((1/2)*t^2 - 1)
I am stuck write here
Last edited by a moderator: