- #1
just.karl
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Sound Intensity "pig calling contest"
In a pig-calling contest, a caller produces a sound with an intensity level of 110db. How many such callers would be required to reach the pain level of 120db?
The equation I think I have to use is (db_1 - db_2)=10*log(power_1 / power_2)
The part that I'm confused on is how to get the two powers onto one side. Can the log be rewritten as (power_1 / power_2)log_10 ? then divide by both sides by log_10? Which would come out to 10=(power_1 / power_2) and I don't know how I would go from there. Provided that everything else is right.
Please help!
In a pig-calling contest, a caller produces a sound with an intensity level of 110db. How many such callers would be required to reach the pain level of 120db?
The equation I think I have to use is (db_1 - db_2)=10*log(power_1 / power_2)
The part that I'm confused on is how to get the two powers onto one side. Can the log be rewritten as (power_1 / power_2)log_10 ? then divide by both sides by log_10? Which would come out to 10=(power_1 / power_2) and I don't know how I would go from there. Provided that everything else is right.
Please help!