- #1
maverick280857
- 1,789
- 5
Hi everyone
Consider the differential equation
[tex]\cos(y'') + xy' = 0[/tex]
How do you determine the order and degree of such a DE?
One way is to write
[tex]y'' = \cos^{-1}(-xy')[/tex]
and say that the order is 2 degree is 1.
But if I do not use the inverse cosine, and observe that the first member on the left hand side is a power series in [itex]y''[/itex], then the order is still 2, but the degree is not defined. What is the resolution to this problem?
PS--This is not homework.
Consider the differential equation
[tex]\cos(y'') + xy' = 0[/tex]
How do you determine the order and degree of such a DE?
One way is to write
[tex]y'' = \cos^{-1}(-xy')[/tex]
and say that the order is 2 degree is 1.
But if I do not use the inverse cosine, and observe that the first member on the left hand side is a power series in [itex]y''[/itex], then the order is still 2, but the degree is not defined. What is the resolution to this problem?
PS--This is not homework.