- #1
griffon
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Q: A solid if formed by adjoining two hemispheres to the ends of a right circular cylinder. The total volume of the solid is 12 cm^3. Find the radius of the cylinder that produces the minimum surface area.
OK, I got about halfway through my problem before I got lost.
V of shpere= 4/3(pi)r^3
V of cylinder= (pi)r^2(h)
total V= 2(4/3*pi*r^30) + (pi*r^2*h)
12=pi*r^2(2*4/3*r+h) which turns into 12/pi*r^2=8/3*r+h
so h=(12/pi*r^2) - (8/3*r)
Now I'm lost.
OK, I got about halfway through my problem before I got lost.
V of shpere= 4/3(pi)r^3
V of cylinder= (pi)r^2(h)
total V= 2(4/3*pi*r^30) + (pi*r^2*h)
12=pi*r^2(2*4/3*r+h) which turns into 12/pi*r^2=8/3*r+h
so h=(12/pi*r^2) - (8/3*r)
Now I'm lost.