- #1
4real4sure
- 26
- 0
For the network shown, show that the resistance Rab = (27/17)ohms .
http://www.webassign.net/pse/p28-28.gif
Figure P28.28
My attempt to the problem:
I got the first following equations:
I1-I3-I2=0
I4+I6-I1=0
I2+I5-I6=0
I3-I4-I5=0
Note that I3 and I4 are currents flowing at the top
I2 and I6 are flowing through 3 and 5 ohm resistances
I1 is connected to a battery at tyhe left side of I2
Any help will be highly highly appreciated!
http://www.webassign.net/pse/p28-28.gif
Figure P28.28
My attempt to the problem:
I got the first following equations:
I1-I3-I2=0
I4+I6-I1=0
I2+I5-I6=0
I3-I4-I5=0
Note that I3 and I4 are currents flowing at the top
I2 and I6 are flowing through 3 and 5 ohm resistances
I1 is connected to a battery at tyhe left side of I2
Any help will be highly highly appreciated!