uofamath114 said:I must be confused then because the way I understood it was a limit where "x-->c-" means that we only consider values less than c. So with the limit x-->(pi)- wouldn't it have to be negative infinity since infinity would be a value greater than pi or is my logic completely wrong.
uofamath114 said:I get 100000 and it gets progressively larger and larger the closer it comes to pi, so am I correct to assume the limit is infinity?
The limit of a function f(x) as x approaches a number c is the value that f(x) approaches as x gets closer and closer to c. It is denoted by the symbol lim f(x) = L, where L is the limit.
To find the limit of a function, plug in values that approach the given value for x. If the function approaches a finite number, that is the limit. If the function approaches infinity, the limit does not exist.
"cscx" stands for the cosecant of x, which is the reciprocal of the sine of x. It can also be written as 1/sinx.
To evaluate the limit of f(x)=cscx as x approaches x-, we need to determine the behavior of the function as x approaches x- from the left side. This can be done by plugging in values that are slightly smaller than x and observing the resulting values of the function. If the values approach a finite number, then that is the limit. If the values approach infinity, the limit does not exist.
No, the limit of f(x)=cscx as x approaches x- cannot be equal to zero. This is because the cosecant function is undefined at certain values of x, such as when x is equal to 0 or a multiple of π. Therefore, the limit of cscx as x approaches x- will either approach a finite number or it will not exist.