- #1
koolkris623
- 19
- 0
Find the equation of the line normal to the curve at (0,0). (Normal lines are perpendicular to the tangent lines)
2y + sinx = xcoxy
I found the derivative to be (cosy - cosx)/ (2+ xsiny)
then the slope tangent is 0...then the slope perpendicular to it is undefined...so then is the normal equation..x=0?
2y + sinx = xcoxy
I found the derivative to be (cosy - cosx)/ (2+ xsiny)
then the slope tangent is 0...then the slope perpendicular to it is undefined...so then is the normal equation..x=0?