- #1
Observatoren
- 16
- 0
Ill start by appologizing for not using LaTex, but i haven't figured out how it works yet and I am a little bit impatient.
The equation is probably a simple one. I am not very trained in math but happen to have some interest in physics, especially astronomy, and this is used in astronomy but i think this is a better place to ask this question, hope i haven't posted this thread all in the wrong place.
To the question. How do I get from 2GMr/D^3=Gm/r^2 to D=(2M/m)^1/3r
A step by step explanation would be appreciated. And again, excuse me if I am not following the general rules for posting but Ill better myself in the future.
Thanks!
The equation is probably a simple one. I am not very trained in math but happen to have some interest in physics, especially astronomy, and this is used in astronomy but i think this is a better place to ask this question, hope i haven't posted this thread all in the wrong place.
To the question. How do I get from 2GMr/D^3=Gm/r^2 to D=(2M/m)^1/3r
A step by step explanation would be appreciated. And again, excuse me if I am not following the general rules for posting but Ill better myself in the future.
Thanks!