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helpinghand
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Using the existence and uniqueness criteria, give the region (call it D) in the x-y plane consisting of all points (xo, yo) such that there is a unique solution. Choose a point in D as your initial condition, show that the equation is exact, then use the fact to solve the associated initial value problem.
2x+4y+(4x-2y)(dy/dx)=0, y(xo)=yo
I know how to solve of exactness, by proving that (dP/dy)=(dQ/dx), but what I don't quite get is how do I figure out what the initial value is, do I just let the inital values of x and y be just some random value and prove for uniqueness or is there a way that I can find what the initial values are?
2x+4y+(4x-2y)(dy/dx)=0, y(xo)=yo
I know how to solve of exactness, by proving that (dP/dy)=(dQ/dx), but what I don't quite get is how do I figure out what the initial value is, do I just let the inital values of x and y be just some random value and prove for uniqueness or is there a way that I can find what the initial values are?
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