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BillJ3986
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Homework Statement
Two heating coils have resistances 12.0 ohms and 6.0 ohms, respectively.
a)What is the Joule heat generated in each if they are connected in parallel to a source of emf of 115V?
b) What if they are connected in series.
Homework Equations
Am I doing this question properly?
The Attempt at a Solution
Since the resistors are in parallel. In order to find R effective I use the formula 1/12.0 +1/6.0=1/4 so my R effective is 4.0 ohms. I then needed to find the current, I. So I used I=Emf/R, I=115/4.0=28.8A, I think that is a little high.I use P=I^2(R), P=28.8^2(12)=9953W to find the joule heating in resistor 1? and then I did the same for the second resistor in parallel. P=28.8^2(6.0)=4976W.
For part B I had to find the current so I did I=Emf/r+r and they are in series so I just added them up to 18 ohms for my R effective. I found I, using I=115V/18ohms= 6.39A. P=6.39^2(12)=490W, second resistor p=6.39^2(6)=245W
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