- #1
IntegrateMe
- 217
- 1
(a) Find the x- and y-coordinates of the relative maximum points of f in terms of b.
(b) Find the x- and y-coordinates of the relative minimum points of f in terms of b.
(c) Show that for all values of b > 0, the relative maximum and minimum points lie on a function of the form y = -ax3 by finding the value of a.
(a)
f(x)=x3-3bx
f'(x)=3x2-3b=0
x2=b
x=+/-sqrt(b)
when x=-sqrt(b),
f(x) = y = -b3/2 - 3b(-b1/2)
(x,y) = ( -sqrt(b) , 2b3/2) f has a maximum
(b)
when x=sqrt(b),
f(x) = y = b3/2 - 3b(b1/2)
(x,y)=(sqrt(b),-2b3/2) f has a minimum
(c)
I'm not sure. Can someone help me with (c)?
Ok, i attempted each part. Did i do anything wrong?
(b) Find the x- and y-coordinates of the relative minimum points of f in terms of b.
(c) Show that for all values of b > 0, the relative maximum and minimum points lie on a function of the form y = -ax3 by finding the value of a.
(a)
f(x)=x3-3bx
f'(x)=3x2-3b=0
x2=b
x=+/-sqrt(b)
when x=-sqrt(b),
f(x) = y = -b3/2 - 3b(-b1/2)
(x,y) = ( -sqrt(b) , 2b3/2) f has a maximum
(b)
when x=sqrt(b),
f(x) = y = b3/2 - 3b(b1/2)
(x,y)=(sqrt(b),-2b3/2) f has a minimum
(c)
I'm not sure. Can someone help me with (c)?
Ok, i attempted each part. Did i do anything wrong?