TaxOnFear said:I would start by assuming atmospheric pressure, also assuming the ice is at 0°C and boiling water is at 100°C.
The temperature of the resulting mixture will be somewhere in between the melting point of ice (0°C) and the boiling point of water (100°C), depending on the exact proportions of ice and water.
No, the total mass of the mixture will remain constant at 2 kg. This is because the ice and water are both in their liquid state and have the same density, so they will occupy the same volume and therefore have the same mass.
The ice will undergo a phase change from solid to liquid, as it melts due to the heat from the boiling water.
The energy in the system will increase due to the heat transfer from the boiling water to the melting ice. This will result in a decrease in the temperature of the boiling water and an increase in the temperature of the melting ice, until they reach a thermal equilibrium.
No, this mixture cannot be used as a coolant as the resulting temperature will be above the freezing point of water, and therefore it will not be able to absorb heat from a system to cool it down.