- #1
maccaman
- 49
- 0
I have just been doing some Riemann Sums, but i must find the midpoint. Now i am doing some research on how to do it but i don't get the formula.
Function i am using is y=x^2, over x=2 and x=12, with n=20 subintervals.
For the left sum i used something like this
1/2 * (2^2 + 2.5^2 + 3^2 + 3.5^2 + ... + 11.5^2)
now for the right i used somethign like this
1/2 * (2.5^2 + 3^2 + 3.5^2 + ... + 12^2)
From my basic understanding, i am a high school student, all i do is this
LEFT (a-b / n) multiplied by (a^2 + ... (every 0.5^2 interval until
11.5^2) (miss out 12 ^2) ).
RIGHT i did the same for right, with the exception of leaving out a^2, and put in b^2 instead.
if someone could help me a bit on the MIDPOINT one would be great, i know the sum, just want to know how to do it.
P.S. I've seen upper and lower, is this the same as right and left. Thanks for any help
Function i am using is y=x^2, over x=2 and x=12, with n=20 subintervals.
For the left sum i used something like this
1/2 * (2^2 + 2.5^2 + 3^2 + 3.5^2 + ... + 11.5^2)
now for the right i used somethign like this
1/2 * (2.5^2 + 3^2 + 3.5^2 + ... + 12^2)
From my basic understanding, i am a high school student, all i do is this
LEFT (a-b / n) multiplied by (a^2 + ... (every 0.5^2 interval until
11.5^2) (miss out 12 ^2) ).
RIGHT i did the same for right, with the exception of leaving out a^2, and put in b^2 instead.
if someone could help me a bit on the MIDPOINT one would be great, i know the sum, just want to know how to do it.
P.S. I've seen upper and lower, is this the same as right and left. Thanks for any help