- #1
missashley
- 34
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A 37 kg box slides down a 35 degree ramp with an acceleration of 1.35 m/s^2. The acceleration of gravity is 9.81 m/s^2.
Find the coefficient of kinetic friction between the box and the ramp.
Ff= MkFn
37 * 1.35 = 49.95 N
Fgx = 49.95 sin 35 = 28.650143
Fgy = 49.95 cos 32 = 40.91664461
Ax = (1/m)(Ff - Fgx)
Ax= ((1/m)(Ff)) - ((1/m)(Fgx))
Ax + ((1/m)(Fgx)) = ((1/m)(Ff))
1.35 + ((1/37)(28.650143)) = ((1/37)(Ff))
2.124328189 = ((1/37)(Ff))
2.124328189 * 37 = Ff
78.600143 = Ff
Mk = 78.600143 / 40.916
Mk = 1.921012391
I think I did something wrong because the coefficient is greater than one
Please check what I did wrong and how can I fix it?
Find the coefficient of kinetic friction between the box and the ramp.
Ff= MkFn
37 * 1.35 = 49.95 N
Fgx = 49.95 sin 35 = 28.650143
Fgy = 49.95 cos 32 = 40.91664461
Ax = (1/m)(Ff - Fgx)
Ax= ((1/m)(Ff)) - ((1/m)(Fgx))
Ax + ((1/m)(Fgx)) = ((1/m)(Ff))
1.35 + ((1/37)(28.650143)) = ((1/37)(Ff))
2.124328189 = ((1/37)(Ff))
2.124328189 * 37 = Ff
78.600143 = Ff
Mk = 78.600143 / 40.916
Mk = 1.921012391
I think I did something wrong because the coefficient is greater than one
Please check what I did wrong and how can I fix it?