- #1
psychfan29
- 9
- 0
How do I derive this equation?!? HELP!
I started with the equation:
y=yinitial + (vinitialsintheta)t -1/2gt^2
I plugged in t=x/(vinitialcostheta)
to get: y=yinitial + x (tantheta) - [(gx^2)/(2(vinitial^2)(cos^2theta))]
Using derivatives, how do I get from this equation:
y=yinitial + x (tantheta) - [(gx^2)/(2(vinitial^2)(cos^2theta))]
to this equation:
(dy)/(dtheta)=
x(sec^2theta)-[(gx^2(tantheta)(sec^2theta))/(vinitial^2)]
I am completely and totally and utterly confused, bewildered, perplexed, and a list of other things.
Plese help!
I started with the equation:
y=yinitial + (vinitialsintheta)t -1/2gt^2
I plugged in t=x/(vinitialcostheta)
to get: y=yinitial + x (tantheta) - [(gx^2)/(2(vinitial^2)(cos^2theta))]
Using derivatives, how do I get from this equation:
y=yinitial + x (tantheta) - [(gx^2)/(2(vinitial^2)(cos^2theta))]
to this equation:
(dy)/(dtheta)=
x(sec^2theta)-[(gx^2(tantheta)(sec^2theta))/(vinitial^2)]
I am completely and totally and utterly confused, bewildered, perplexed, and a list of other things.
Plese help!