- #1
vg19
- 67
- 0
Homework Statement
To find the voltage-current relationship of a capcitor, integrate both sides of
i = C(dv/dt)
The Attempt at a Solution
In the book they say, v = (1/C)(The Integral from -tve infitity to t) of i dt.
or
v = (1/C)(The Integral from tnot to t) of i dt + v(tnot)
I am trying to understand why they integrated from negative infinity. Why not start the integration at 0. I also do not undersstand in the second equation where the + v(tnot) came from.
Thanks in advance