## Single slit diffraction maxima

Hi, I was wondering if anyone could help me with this problem.

Calculate the distance y between adjacent maxima in single slit diffraction patterns. Your answer should be given in terms of a, λ and D. (a is the length of the slit, D is the distance between the slit and the screen and λ is the wavelength of the light).

Ok, so I know how to get the minima of single slit diffraction. You just break it down into many rays going through the slit to get a*sin O=nλ. So is it just the same for the maxima? Say for two rays you would get (a/2)*sin O=nλ (nλ since you want the two rays to constructively interfere and when its nλ they are perfectly in phase) so in general it would be be a*sin O = 2nλ. This doesn't really make much sense though...cause the 2nλ distances are just multiples of nλ which is the minima.
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 Recognitions: Homework Help For a single slit experiment, the condition for constructive interference is: $$dsin\theta = (n + \frac{1}{2})\lambda$$ which is derived geometrically.
 Mentor Blog Entries: 1 While it's easy to find the minima for the single slit diffraction pattern, there's no simple formula for the maxima. The positions of the minima are given by: $$dsin\theta = n\lambda$$ The maxima are not found exactly in the middle between the minima. See here for details: http://scienceworld.wolfram.com/phys...ingleSlit.html (Depending upon the level of the course, they may want you to use mezarashi's formula as a rough approximation, but realize that this is not really correct.)

## Single slit diffraction maxima

Hi everyone. Could anyone please explain why there is no simple argument to understand where the maxima of a single slit diffraction pattern are found? Why doesn't the same argument as for the minima work? I'm a freshman in university btw so you know what level of education I have.Thanks!
 Hi,I have been facing some problem in single slit diffraction and need precise description. we know from single slit diffraction,in term of destructive interfere a sinθ=nλ and constructive interfere a sinθ=(2n+1)λ/2.Here (a is the length of the slit, D is the distance between the slit and the screen and λ is the wavelength of the light and θ is the diffraction angle). But we know from the constructive interference in term of sound or light, path difference=nλ (even multiples of λ) and in case of destructive interference,path difference=(2n+1)λ/2(uneven multiples of λ) . Could anybody describe thoroughly, in term of single slit diffraction,why the condition of constructive and destructive interference place opposite to each other. Please anyone solve my problem.