- #1
stunner5000pt
- 1,461
- 2
Find the magnetic field at the center of a rectangular loop with sides 2a and 2b.
well ok due to the sides with length 2a
[tex] B_{A} = \frac{\mu_{0} i}{2 \pi B} \frac{A}{\sqrt{\frac{A^2}{4} + B^2}} [/tex]
and due to 2B sides
[tex] B_{B} = \frac{\mu_{0} i}{2 \pi B} \frac{B}{\sqrt{\frac{B^2}{4} + A^2}} [/tex]
adding these two up yields the answer? Is this right? Please advise! Thanks!
well ok due to the sides with length 2a
[tex] B_{A} = \frac{\mu_{0} i}{2 \pi B} \frac{A}{\sqrt{\frac{A^2}{4} + B^2}} [/tex]
and due to 2B sides
[tex] B_{B} = \frac{\mu_{0} i}{2 \pi B} \frac{B}{\sqrt{\frac{B^2}{4} + A^2}} [/tex]
adding these two up yields the answer? Is this right? Please advise! Thanks!