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Maclaurin Series used to find associated radius of convergence Q!

by badtwistoffate
Tags: convergence, maclaurin, radius, series
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badtwistoffate
#1
Dec11-05, 08:35 PM
P: 85
I have the Maclaurin series for cos (x), is their a way to find its radius of convergence from that?

ALSO
Is there a trick to find the shorter version of the power series for the Maclaurin series, I can never seem to find it so instead of the long series with each term but like E summation (the series)
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shmoe
#2
Dec11-05, 08:59 PM
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Quote Quote by badtwistoffate
I have the Maclaurin series for cos (x), is their a way to find its radius of convergence from that?
you can try the ratio test.

Quote Quote by badtwistoffate
ALSO
Is there a trick to find the shorter version of the power series for the Maclaurin series, I can never seem to find it so instead of the long series with each term but like E summation (the series)
Err, do you mean writing the series using the sigma notation instead of the first few terms followed by some ...? You want to look for patterns in the coefficients. No real trick, practice will help though.
badtwistoffate
#3
Dec11-05, 09:01 PM
P: 85
Quote Quote by shmoe
you can try the ratio test.
Err, do you mean writing the series using the sigma notation instead of the first few terms followed by some ...? You want to look for patterns in the coefficients. No real trick, practice will help though.
Yeah i tried the ratio test, but the radius of convergence it sayed in the big is infinity, how is that possible as it has to be n < 1?

shmoe
#4
Dec11-05, 09:20 PM
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Maclaurin Series used to find associated radius of convergence Q!

Quote Quote by badtwistoffate
Yeah i tried the ratio test, but the radius of convergence it sayed in the big is infinity, how is that possible as it has to be n < 1?
I don't understand what you're saying, what's "in the big" mean? What are you calling n that it has to be less than 1?
badtwistoffate
#5
Dec11-05, 09:26 PM
P: 85
Quote Quote by shmoe
I don't understand what you're saying, what's "in the big" mean? What are you calling n that it has to be less than 1?
Sorry I ment to say in the book the radius of convergence is infinity, how is that possible seeing the result of the ratio test gives you L and it has to be less then 1? how to you get that radius of infinity?
shmoe
#6
Dec11-05, 10:26 PM
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You should have found that for *any* value of x, the limit the ratio test gives is always less than 1, hence the series converges for all values of x and we say the radius of convergence is infinity.


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