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I'm stuck to prove Nilpotent Matrix |
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| Oct17-06, 10:21 AM | #1 |
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I'm stuck to prove Nilpotent Matrix
Hi all,
If a square matrix A of dimension n*n is a nilpotent matrix,i.e, A^k=0 for k>=m iff A has eigenvalues 0 with multiplicity n and index m or less. I did prove by induction if A^k=0 then all the eigenvalues are zero. I'm lost when I want to prove the oppesite, i.e, if all eigenvalues are zero then A^k=0? Please help |
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| Oct17-06, 12:02 PM | #2 |
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Recognitions:
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Put it in jordan normal form and it all drops out. Alternatively just think about the characteristic poly.
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