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I'm stuck to prove Nilpotent Matrix 
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#1
Oct1706, 10:21 AM

P: 7

Hi all,
If a square matrix A of dimension n*n is a nilpotent matrix,i.e, A^k=0 for k>=m iff A has eigenvalues 0 with multiplicity n and index m or less. I did prove by induction if A^k=0 then all the eigenvalues are zero. I'm lost when I want to prove the oppesite, i.e, if all eigenvalues are zero then A^k=0? Please help 


#2
Oct1706, 12:02 PM

Sci Advisor
HW Helper
P: 9,396

Put it in jordan normal form and it all drops out. Alternatively just think about the characteristic poly.



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