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tandoorichicken
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A large storage tank is filled with water. Neglecting viscosity, show that the speed of water emerging through a hole in the side a distance h below the surface is [itex] v = \sqrt{2gh} [/tex].
Originally posted by tandoorichicken
A large storage tank is filled with water. Neglecting viscosity, show that the speed of water emerging through a hole in the side a distance h below the surface is [itex] v = \sqrt{2gh} [/tex].
The equation for calculating the speed of water emerging from a large tank is [itex] \sqrt{2gh} [/tex], where g is the acceleration due to gravity (9.8 m/s^2) and h is the height of the water level in the tank.
The speed of water emerging from a large tank is directly proportional to the square root of the height of the water level. This means that as the water level increases, the speed of water emerging also increases.
The square root in the equation accounts for the conversion of potential energy (due to the height of the water level) into kinetic energy (in the form of speed). It also takes into account the fact that the pressure at the bottom of the tank increases as the depth of water increases.
Yes, the acceleration due to gravity is a constant in the equation and is represented by the letter g. However, it may vary slightly depending on location and altitude.
The equation can be applied to all types of tanks as long as the water level is constant and the tank is large enough for the flow of water to be considered as a free fall. However, it may not be accurate for tanks with irregular shapes or for situations where the water level is not constant.