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Replace forces with couple 
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#1
Feb807, 03:27 PM

P: 203

1. The problem statement, all variables and given/known data
I've attached an image. The question states: Replace the three forces shown, with an equivalent forcecouple system at point O(origin). I've got a little ways, but I am stuck at the couple. I don't know how to use the distance in the couple. Need to know what distance to use, and from where. 2. Relevant equations R = Fx + Fy C = Mo = ra/o x Fa + rb/o x Fb + rc/o x Fc(is this correct, or do I use x and y?)this is the part where I'm stuck. magnitude C = sqrt(Cx^2 + Cy^2) 3. The attempt at a solution Fx = 200cos60 + 300cos45 + 250cos30 = 528.6 i Fy = 200sin60 + 300sin45  250sin30 = 260.3 j R = 528.6 i + 260.3 j C = Mo = ??? Am I correct up to this point too? sample exam1.bmp 


#2
Feb807, 05:50 PM

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#3
Feb807, 06:28 PM

P: 203

Ok, I did find the resultant(R).
And, to find the couple, don't I just find the moment(at the origin)? Here goes...but this is where I get confused. 528.6(9) + 260.3(30)...i have no clue, I know this isn't right. Any way you could show me like part of how to do it? So I get the concept? 


#4
Feb807, 07:11 PM

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Replace forces with couple



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