What Does the Y-Intercept and Slope Indicate in an Acceleration vs. Mass Graph?

AI Thread Summary
In an acceleration vs. mass graph, the y-intercept indicates the acceleration of the system when no mass is involved, although this scenario is mathematically unrealistic. The graph's slope, measured in m/s²/kg, reflects the gravitational force acting on the mass, suggesting that as mass increases, acceleration decreases due to the inability to overcome inertia. When the x-axis value approaches zero, it signifies an infinite mass scenario, where acceleration cannot occur. Additionally, when the difference in masses equals zero, acceleration also equals zero, reinforcing the relationship between mass and acceleration. Understanding these concepts is crucial for interpreting the dynamics of force and motion in physics.
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Homework Statement


If in an acceleration vs. mass (kg) graph (where the x-axis reads (1/m1+m2), the inverse of the sum of masses), the best fit does interesect with the origin because if x = zero, or (1/m1+m2) = o, the final solution is unreal since it is mathematically incorrect to divide one by zero.

Likewise, in an acceleration vs. differences of masses, best interesects with origin since when m1-m2=0, acceleration, as as result, equals to zero.

Finally, would it be correct to stay that the y interest of an acceleration vs. mass graph represents the acceleration of the system when 0 masses are involved, or does it repersent the gravitational mass (resistance)?

Also, how would a slope of such a graph hint at the gravitational force acting on the mass, where the units of the slop are m/s²/kg?

Homework Equations





The Attempt at a Solution

 
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When 1/m -> 0 whe are dealing with a situation where the mass is becoming very large and therefore the force will not be able to accelerate it (or get it to move out of rest and not succeeding). That is we are trying to push a very heavy object.
 
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