# Direct product

by barbiemathgurl
Tags: product
 P: 291 We can use the Chinese Remainder Theorem on this one. Define the mapping, $$\phi: G_{nm}\mapsto G_n\times G_m$$ As, $$\phi(x) = (x\bmod{n} , x\bmod{m})$$ 1)The homomorphism part is trivial. 2)The bijection part is covered by Chinese Remainder Theorem.