- #1
lLovePhysics
- 169
- 0
I'm stuck on this limit function and I don't know what to do next. Please help me out. Thanks!
[tex]\lim_{x\rightarrow 0^{+}}(\frac{\csc2x}{x})[/tex]
I just turned csc2x into 1\sin2x so then I have:
[tex] \lim_{x\rightarrow 0^{+}} (\frac{1}{x\sin2x})[/tex]
Then I used the trig identity: sin2x=2sinxcosx
...but I'm not sure if this is going to take me anywhere.
I know that [tex]\lim_{x\rightarrow c} \sin x = \sin c[/tex] but I'm not sure how to incoporate that identity in this problem.
[tex]\lim_{x\rightarrow 0^{+}}(\frac{\csc2x}{x})[/tex]
I just turned csc2x into 1\sin2x so then I have:
[tex] \lim_{x\rightarrow 0^{+}} (\frac{1}{x\sin2x})[/tex]
Then I used the trig identity: sin2x=2sinxcosx
...but I'm not sure if this is going to take me anywhere.
I know that [tex]\lim_{x\rightarrow c} \sin x = \sin c[/tex] but I'm not sure how to incoporate that identity in this problem.