
#1
Oct3107, 04:00 PM

P: 3

Hi, I am new to manifold and having a hard time on it. Could anyone please help me on the following problem. Please write down your thoughts. Thanks alot.
Prove that (S^n) X R is parallelizable for all n. 



#2
Nov107, 12:11 AM

P: 448

Show us what you've done so far and tell us precisely where you're stuck.




#3
Nov107, 01:04 PM

P: 3

Hi,I tried to show S^nXR is parallelizable by showing S^nXR is diffeomorphic to R^n+1\{0} so if R^n+1\{0} is parallelizable then the problem solved. But I just don't know how to show R^n+1\{0} is parallelizable.




#4
Nov607, 07:56 PM

P: 28

Parallelizable ManifoldA global frame for R^(n+1) is... (1,0,...,0) (0,1,0,...,0) . . . (0,...,0,1) 


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