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Complex mathematica tutorial? 
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#1
Dec907, 08:54 AM

P: 12

so i was kind of wondering if anyone knows of any mathematica tuorials for how to operate with complex numbers (i know how to do it by hand but solving a set of 5 equations all complex just seems suicidal :D )
so any help d be appreciated 


#2
Dec907, 08:59 AM

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What about
Solve[{ a^2 + b^2 == 2, b  3 c == \[ImaginaryI], 2 c  3 a == 1 + \[ImaginaryI], d + 4 == Sqrt[e], e + a == 3}, {a, b, c, d, e} ] just as you would solve a normal set of equations? 


#3
Dec907, 02:17 PM

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P: 10,429

There's really nothing special at all about using complex numbers in Mathematica.
 Warren 


#4
Dec1007, 06:46 AM

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P: 4,300

Complex mathematica tutorial?
By the way, if the equations are linear, there is nothing suicidal about it. Just write them in matrix form and rowreduce (the joy of every student)
Oh, and before I forget, you make the imaginary i in Mathematica by typing I (capital i) or [Escape]ii[Escape] 


#5
Dec1007, 11:32 AM

P: 12

hmm yeah i wish they were linear
well only problem i really got is that i dont know how to conjugate Exp[ i x] or to make shown as Cosx + i Sinx P.S equations were: a1  a2 + b1  b2 (20/197) Sqrt[2555] (a2  b2) Sqrt[1 + x] + 20/197 Sqrt[2555] (a1  b1) Sqrt[x] a3 exp[20/197 \[ImaginaryI] Sqrt[2555] Sqrt[2 + x]] + b2 exp[(20/197) \[ImaginaryI] Sqrt[2555] Sqrt[1 + x]] + a2 exp[20/197 \[ImaginaryI] Sqrt[2555] Sqrt[1 + x]] (20/197) Sqrt[2555] a3 Sqrt[2 + x] exp[20/197 \[ImaginaryI] Sqrt[2555] Sqrt[2 + x]] + 20/197 Sqrt[2555] Sqrt[1 + x] (a2 exp[20/197 \[ImaginaryI] Sqrt[2555] Sqrt[1 + x]]  b2 exp[20/197 \[ImaginaryI] Sqrt[2555] Sqrt[1 + x]]) (dunno latex so sry for the uglyness) 


#6
Dec1007, 01:00 PM

P: 687

you can use ExpToTrig[...] to convert the exponentials to trigonometric functions.
I think there is a conjugation function somewhere... 


#7
Dec1007, 03:01 PM

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You'd never guess it... it's called Conjugate[...]
i.e. Conjugate[4 + 3I] gives 4  3I 


#8
Dec1007, 04:27 PM

P: 687

The mathematica help is pretty good, just do a search in the mathematica help browser for whatever you're trying to do, there is probably a function already designed for it.



#9
Dec1107, 08:04 AM

P: 12

i think i actually managed it :D did the trig thingy and then used Conjugate (that one was silly obvious /blush)
and i got a result thank you :) 


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