## complex mathematica tutorial?

so i was kind of wondering if anyone knows of any mathematica tuorials for how to operate with complex numbers (i know how to do it by hand but solving a set of 5 equations all complex just seems suicidal :D )

so any help d be appreciated
 Blog Entries: 5 Recognitions: Homework Help Science Advisor What about Solve[{ a^2 + b^2 == -2, b - 3 c == \[ImaginaryI], 2 c - 3 a == 1 + \[ImaginaryI], d + 4 == Sqrt[e], e + a == -3}, {a, b, c, d, e} ] just as you would solve a normal set of equations?
 Recognitions: Gold Member Science Advisor Staff Emeritus There's really nothing special at all about using complex numbers in Mathematica. - Warren

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## complex mathematica tutorial?

By the way, if the equations are linear, there is nothing suicidal about it. Just write them in matrix form and row-reduce (the joy of every student)

Oh, and before I forget, you make the imaginary i in Mathematica by typing I (capital i) or [Escape]ii[Escape]
 hmm yeah i wish they were linear well only problem i really got is that i dont know how to conjugate Exp[ i x] or to make shown as Cosx + i Sinx P.S equations were: a1 - a2 + b1 - b2 -(20/197) Sqrt[2555] (a2 - b2) Sqrt[-1 + x] + 20/197 Sqrt[2555] (a1 - b1) Sqrt[x] -a3 exp[20/197 \[ImaginaryI] Sqrt[2555] Sqrt[-2 + x]] + b2 exp[-(20/197) \[ImaginaryI] Sqrt[2555] Sqrt[-1 + x]] + a2 exp[20/197 \[ImaginaryI] Sqrt[2555] Sqrt[-1 + x]] -(20/197) Sqrt[2555] a3 Sqrt[-2 + x] exp[20/197 \[ImaginaryI] Sqrt[2555] Sqrt[-2 + x]] + 20/197 Sqrt[2555] Sqrt[-1 + x] (a2 exp[20/197 \[ImaginaryI] Sqrt[2555] Sqrt[-1 + x]] - b2 exp[20/197 \[ImaginaryI] Sqrt[2555] Sqrt[-1 + x]]) (dunno latex so sry for the uglyness)
 you can use ExpToTrig[...] to convert the exponentials to trigonometric functions. I think there is a conjugation function somewhere...
 Blog Entries: 5 Recognitions: Homework Help Science Advisor You'd never guess it... it's called Conjugate[...] i.e. Conjugate[4 + 3I] gives 4 - 3I
 The mathematica help is pretty good, just do a search in the mathematica help browser for whatever you're trying to do, there is probably a function already designed for it.
 i think i actually managed it :D did the trig thingy and then used Conjugate (that one was silly obvious /blush) and i got a result thank you :)