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Complex mathematica tutorial?

by liskawc
Tags: complex, mathematica, tutorial
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liskawc
#1
Dec9-07, 08:54 AM
P: 12
so i was kind of wondering if anyone knows of any mathematica tuorials for how to operate with complex numbers (i know how to do it by hand but solving a set of 5 equations all complex just seems suicidal :D )

so any help d be appreciated
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CompuChip
#2
Dec9-07, 08:59 AM
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What about

Solve[{
a^2 + b^2 == -2,
b - 3 c == \[ImaginaryI],
2 c - 3 a == 1 + \[ImaginaryI],
d + 4 == Sqrt[e],
e + a == -3},
{a, b, c, d, e}
]

just as you would solve a normal set of equations?
chroot
#3
Dec9-07, 02:17 PM
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There's really nothing special at all about using complex numbers in Mathematica.

- Warren

CompuChip
#4
Dec10-07, 06:46 AM
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Complex mathematica tutorial?

By the way, if the equations are linear, there is nothing suicidal about it. Just write them in matrix form and row-reduce (the joy of every student)

Oh, and before I forget, you make the imaginary i in Mathematica by typing I (capital i) or [Escape]ii[Escape]
liskawc
#5
Dec10-07, 11:32 AM
P: 12
hmm yeah i wish they were linear

well only problem i really got is that i dont know how to conjugate Exp[ i x] or to make shown as Cosx + i Sinx

P.S equations were:
a1 - a2 + b1 - b2

-(20/197) Sqrt[2555] (a2 - b2) Sqrt[-1 + x] +
20/197 Sqrt[2555] (a1 - b1) Sqrt[x]

-a3 exp[20/197 \[ImaginaryI] Sqrt[2555] Sqrt[-2 + x]] +
b2 exp[-(20/197) \[ImaginaryI] Sqrt[2555] Sqrt[-1 + x]] +
a2 exp[20/197 \[ImaginaryI] Sqrt[2555] Sqrt[-1 + x]]

-(20/197) Sqrt[2555] a3 Sqrt[-2 + x]
exp[20/197 \[ImaginaryI] Sqrt[2555] Sqrt[-2 + x]] +
20/197 Sqrt[2555]
Sqrt[-1 +
x] (a2 exp[20/197 \[ImaginaryI] Sqrt[2555] Sqrt[-1 + x]] -
b2 exp[20/197 \[ImaginaryI] Sqrt[2555] Sqrt[-1 + x]])

(dunno latex so sry for the uglyness)
NeoDevin
#6
Dec10-07, 01:00 PM
P: 687
you can use ExpToTrig[...] to convert the exponentials to trigonometric functions.

I think there is a conjugation function somewhere...
CompuChip
#7
Dec10-07, 03:01 PM
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You'd never guess it... it's called Conjugate[...]
i.e. Conjugate[4 + 3I] gives 4 - 3I
NeoDevin
#8
Dec10-07, 04:27 PM
P: 687
The mathematica help is pretty good, just do a search in the mathematica help browser for whatever you're trying to do, there is probably a function already designed for it.
liskawc
#9
Dec11-07, 08:04 AM
P: 12
i think i actually managed it :D did the trig thingy and then used Conjugate (that one was silly obvious /blush)
and i got a result

thank you :)


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