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Finding Ranges of inverse functions 
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#19
Jun508, 02:27 PM

P: 656

range: y > 1
because as x tends to infinity y tends to 1. And as the domain says x>1 we can ignore the curve in the other quadrant Right? 


#20
Jun508, 02:33 PM

P: 238

Yes, you are correct. I forgot that the original condition was x>1 :P



#21
Jun508, 02:34 PM

P: 656

Thanks a load :)



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