Tangential and radial acceleration of particle

DG1102
Messages
1
Reaction score
0

Homework Statement



In the case of a speeding particle undergoing circular motion:

a) the tangential acceleration is int he direction of the velocity vector and the radial acceleration points in the direction of the position vector
b)the tangential acceleration is perpendicular to the velocity vector and the radial acceleration points perpendicular to the position vector
c)the tangental acceleration is opposite the velocity vector and the radial acceleration points opposite the position vector
d)the tangential acceleration is int he direction of the velocity vector and the radial acceleration poitns opposite the position vector.

The Attempt at a Solution



I think the answer is either a or d, I'm not sure which way the radial acceleration points in this case.
 
Physics news on Phys.org
The position vector points from the origin (presumably the center of the circle in this case) outward to the particle. So, ask yourself what the motion of the particle would be if it had a tangential velocity and was (a) accelerating outward and (d) accelerating inward ...circular motion is only possible in one of these two cases.
 
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
The value of H equals ## 10^{3}## in natural units, According to : https://en.wikipedia.org/wiki/Natural_units, ## t \sim 10^{-21} sec = 10^{21} Hz ##, and since ## \text{GeV} \sim 10^{24} \text{Hz } ##, ## GeV \sim 10^{24} \times 10^{-21} = 10^3 ## in natural units. So is this conversion correct? Also in the above formula, can I convert H to that natural units , since it’s a constant, while keeping k in Hz ?
Back
Top