Solving 2kg Fan-Cart Motion: Acceleration, Velocity & Displacement

AI Thread Summary
The discussion focuses on calculating the motion parameters of a 2 kg fan-cart subjected to a 4 N forward force and 1 N frictional force. Using Newton's second law, the net force is determined to be 3 N, resulting in an acceleration of 1.5 m/s². The velocity at 3 seconds is calculated to be 4.5 m/s, while at 5 seconds, it reaches 7.5 m/s. The displacement between 3 and 5 seconds is found to be 11.5 meters, and the total displacement from 0 to 5 seconds is 18.75 meters. The average velocity during the interval between 3 and 5 seconds is then computed based on the displacement results.
jammhawk
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Homework Statement


A 2 kg fan-cart is in linear motion; it experiences 4 N forward force due to the fan.

Assume that the 2kg fan-cart rolls under fan's force, between the weels and track there is 1N frictional force.

1. its acceleration
2. its velocity 3 second after start
3. its velocity 5 second after start
4. its displacement between 3s and 5s
5. its displacement between 0s and 5s
6. its average velocity using the result of 4

Homework Equations





The Attempt at a Solution



Any HELP will be GREAT!
 
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You are going to have to show how you would apply Newton's 2nd law and the general kinematic motion equations.
 
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