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Tension between 3 blocks

by ScullyX51
Tags: acceleration, tension
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ScullyX51
#1
Oct31-08, 09:21 PM
P: 36
1. The problem statement, all variables and given/known data
Three identical blocks connected by ideal strings are being pulled along a horizontal frictionless surface by a horizontal force F_vec. (Intro 1 figure) The magnitude of the tension in the string between blocks B and C is T = 3.00 N. Assume that each block has mass m = 0.400 kg

What is the magnitude F of the force?
What is the tension T:AB in the string between block A and block B?


2. Relevant equations
F=ma



3. The attempt at a solution
I am unsure of how to approach the first part of the problem. For the second part, since t is the only force acting this the block,
I have: T=ma
I solve for A from the first part of the equation where t is given as follows:
t=ma
3=.400a
a=3/.4
a=7.5 m/s^2

I plugged this into to solve for the other tension as follows:
t=ma
t=.4*7.5
t=3

Mastering physics is saying the tension and the acceleration is wrong. Where did I screw up?
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LowlyPion
#2
Oct31-08, 09:40 PM
HW Helper
P: 5,343
What is the order of your blocks?

T <---{A}--{B}--{C}

Generally, whatever your force is, the acceleration will be F/(3*m) and then the intermediate tensions would be whatever force is needed to keep the blocks remaining moving with that acceleration.

In the example above that would be 2/3*F between A:B and 1/3*F between B:C


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