| Thread Closed |
Changing the variable in multiple integrals |
Share Thread | Thread Tools |
| Jan22-09, 11:29 AM | #1 |
|
|
Changing the variable in multiple integrals
1. The problem statement, all variables and given/known data
Evaluate [tex]\int\int(x-y)^2sin^2(x+y)dxdy[/tex] taken over a square with successive vertices (pi,0), (2pi,pi), (pi,2pi), (0,pi). 2. Relevant equations [tex]I = \int\int_{K} f(x,y)dxdy = \int\int_{K'} g(u,v)*J*dudv[/tex] where J is the Jacobian. 3. The attempt at a solution Okay so I've just been learning this for the first time, so I may be doing it completely wrong! I used the transformations u=x-y, v=x+y which give the Jacobian as 2. Now i wasn't sure how to get the new limits for the integrals. What I did was apply the transformation above to give new vertices: (pi,0) -> (pi,pi) (0,pi) -> (-pi,pi) (pi,2pi) -> (-pi,3pi) (2pi,pi) -> (pi,3pi) This gives a simple rectangle, so then i just wrote [tex]I = 2*\int^{3\pi}_{\pi}\int^{\pi}_{-\pi}u^2sin^2(v)dudv = \frac{4\pi^{4}}{3}.[/tex] I wish this was right, but i've a feeling it's not :-( Any help greatly appreciated! |
| Jan22-09, 01:47 PM | #2 |
Recognitions:
|
The rectangle looks ok. But haven't you got the jacobian factor upside down?
|
| Jan22-09, 02:31 PM | #3 |
|
|
Ah yeah, should be 1/2. Other than that though does my method look correct?
Thanks. |
| Jan22-09, 02:34 PM | #4 |
Recognitions:
|
Changing the variable in multiple integrals |
| Thread Closed |
| Thread Tools | |
Similar Threads for: Changing the variable in multiple integrals
|
||||
| Thread | Forum | Replies | ||
| Multiple integral | Calculus & Beyond Homework | 2 | ||
| Multiple Integral question | Calculus & Beyond Homework | 2 | ||
| Tricky Multiple integral word problem | Calculus | 18 | ||
| Induction: 3^(2n) - 1 is an integral multiple of 8 | Calculus & Beyond Homework | 17 | ||
| multiple choice def integral question | Calculus & Beyond Homework | 6 | ||