What questions can you use the quadratic formula for?

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    Formulae Quadratic
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The quadratic formula can be applied to the equations provided, even when there is no constant term (c), by setting c = 0. To use the formula, the equation must be rearranged to equal zero. If the equation does not yield real roots, the solutions will be imaginary. It's important to ensure that the correct form of the formula is used, particularly regarding the signs in the equation. The discussion emphasizes the necessity of setting the y value to zero to utilize the quadratic formula effectively.
JakePearson
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hey guys, could u use the quadratic formula;

x = -b +/- sqrt (-b2 - 4ac)
2a
for the following questions;

y = 4x2 - x

y = 4x2 -1

y = x2 + 4

and

y = -2x2 + 4x

i ask this as there is no value for (c)

help me :)
 
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Hi JakePearson! :smile:

(have a square-root: √ and a ± :wink:)

Yup! You can always use that formula …

just put c = 0 (or b = 0 as the case may be) :biggrin:​
 
You need to show working before anyone can help you.

If there is no real root for an answer, usually means the answer is imaginary. As is the case for c)
 
Last edited:
cheers tiny-tim, thanks, ill use those :)
 
JakePearson said:
x = [-b +/- sqrt (+b[/color]2 - 4ac)]/2a
Note correction, there's no minus sign in front of the 'b squared' term
y = 4x2 - x = 0 [/color]
Note that the y value must be zero in order to use the quadratic formula
 
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