Torque Equilibrium on a Pivot

by JamesEarl
Tags: equilibrium, pivot, torque
JamesEarl is offline
Oct16-09, 08:12 PM
P: 9
1. The problem statement, all variables and given/known data

The two objects in the figure below are balanced on the pivot, with m = 2.4 kg. What is the distance d?

2. Relevant equations


3. The attempt at a solution

2.4kg + 4.0 kg= 6.4kg
6.4kg/2= 3.2kg on each side of pivot
Looking at the right half, 1.2kg+4kg= 5.2kg.
3.2kg/5.2kg * 1m = 0.615 m from right side
So 1.38 m from left side = d...THIS ANSWER IS WRONG

Basically, I understand all the main concepts, I got everything else on my homework right, but for some reason this problem has me stuck. Any help would be appreciated!
Phys.Org News Partner Science news on
NASA's space station Robonaut finally getting legs
Free the seed: OSSI nurtures growing plants without patent barriers
Going nuts? Turkey looks to pistachios to heat new eco-city
rl.bhat is offline
Oct16-09, 11:33 PM
HW Helper
P: 4,442
Find the torque by the center of masses about the left end.
From the left end center of masses produce clockwise torque.
The reaction of the center of masses on pivot produce counterclockwise torque. Equate them to find d.

Register to reply

Related Discussions
Torque/Equilibrium Introductory Physics Homework 9
Equilibrium and Torque Introductory Physics Homework 8
Hanging sign, torque and pivot points Introductory Physics Homework 1
Magnitude of the Torque generated at Pivot Point. Introductory Physics Homework 4
Torque? Rotation it has the Word Pivot.... Introductory Physics Homework 2